Balancing the Cycle
June 3, 2011 5 Comments
Well the basic question was why is it easier to balance the cycle when it is moving fast than when it is stationary. So lets look at it.
First, why does the cycle fall?
For the cycle to be stable it should be in an orientation in which its centre of gravity is at a point directly above the line the joining the points of contact of the tyres with the road. This is an unstable equilibrium, so even a slight disturbance would send it to the more stable equilibrium i.e. flat on the ground.
Next, why doesn’t it always fall?
Well when we are riding one, if there is a small disturbance towards one side then our body balances it by moving itself.
So why is it easy when the cycle is moving than when at rest?
This is the question I wanted to know the answer of. I simplified the case and made a physical model to study it.
The model has a wheel free to rotate about its centre along any axis. The centre of the wheel is fixed. And there is no gravity.
It is set to rotate about the axis of the wheel. Let the moment of Inertia of the wheel be I and the angular velocity ω. The small disturbance can be modelled using a massless particle with momentum p doing an inelastic collision with the wheel.
If we look at the angular momentum about the centre of the wheel. Before the collision Iω along the axis of the wheel and pR perpendicular to it. During the collision all the external force is generated at the centre so there should be no change of angular about this point. Finally there is only the wheel left so it should have Iω along the axis and pR perpendicular to it. So it will have an angular momentum which is at an angle tan-1(pr/Iω) to original direction. We can see that this disorientation increases with decreasing value of ω. So the same impulse creates a smaller disorientation when the wheel is rotating faster.




















